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Topic: MidiInput event & GetMidiInputRaw() (Read 1829 times) |
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Linus
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MIDI-OX Rules!
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MidiInput event & GetMidiInputRaw()
« on: Mar 24th, 2003, 5:58pm » |
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Hello,
I'm trying to write a routine in C#, which maps patches to specified ports.
My problem: I need to know the channel on which a patch is changed, to correctly map all other events on this channel to the specified out port. But the MidiInput event, does not send the channel. So, I tried to use the GetMidiInputRaw() method, when the event is fired. But when I call the method, no further MidiInput events are fired. Is this by design?
My second problem: To circumgo the first problem, I tried simply to call GetMidiInputRaw() in a loop, but it seems that the status is always 192 after & 0x000000F0 (according documentation) to raw input value, although the channel and data values are changing
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Jamie OConnell
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Re: MidiInput event & GetMidiInputRaw()
« Reply #1 on: Mar 25th, 2003, 11:14am » |
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Quote:| I need to know the channel on which a patch is changed, to correctly map all other events on this channel to the specified out port. But the MidiInput event, does not send the channel. |
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In MIDI messages, the channel information is always supplied, but it is encoded as part of the status byte. The low 4 bits of the status represent the channel (0 - 15, or 00 - 0F Hex). You need to add one to this value to get the common human representation of channel (1 - 16).
To obtain the channel in scripting, you would And the status with 0F:
channel = (status & 0x0F) + 1
If you need to use the channel in another status message, do not add one: low-level MIDI numbers channels 0 -15.
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--Jamie
Music is its own reward.
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